Answer:
Here it is given that AB∣∣CD
∠x+80∘=∠BCD (alt angles)
⇒∠x+80∘=116∘
⇒∠x+116∘−80∘
⇒∠x=36∘
Now at point B
∠y+∠x+80∘=180∘ (straight angle)
∠y=180∘−116∘
∠y=64∘
Hence, ∠x=36∘ and ∠y=64∘
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Answer:
Here it is given that AB∣∣CD
∠x+80∘=∠BCD (alt angles)
⇒∠x+80∘=116∘
⇒∠x+116∘−80∘
⇒∠x=36∘
Now at point B
∠y+∠x+80∘=180∘ (straight angle)
∠y=180∘−116∘
∠y=64∘
Hence, ∠x=36∘ and ∠y=64∘