In a double slit experiment, the distance between the slits is 3 mm and the slits are 2 m away from the screen. Two interference patterns can be seen on the screen one due to light with wavelength 480 nm, and the other due to light with wavelength 600 nm. What is the separation on the screen between the fifth order bright fringes of the two interference patterns?
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Answer:
d= 3 mm
D= 2m
wavelength1= 480nm
wavelength2= 600nm
5th bright fringe of wavelength 1= 5lambda (D)/d
= 5* 480nm* 2/3mm
= 1.6mm
5th bright fringe of wavelength 2 = 5lambda (D)/d
= 5*600nm * 2/3mm
= 2mm
separation= 2-1.6
= 0.4mm