In a cricket match, a batswoman hits a boundary 6 times out of 30 balls she plays. Find the probability that she did not hit a boundary.. Created by TbiaSamishta. Math

Hello!Let be the event of hitting the boundary.Then,Now, :Cheers!

In a cricket match, a batswoman hits a boundary 6 times out of 30 balls she play...

iHelper Hello!

Let $\bf{E}$ be the event of hitting the boundary.

Then,

$\sf P(E) = \dfrac{\sf Favourable \:outcomes}{\sf Total\:number\:of \:outcomes} = \dfrac{6}{30} = \bf{0.2}$

Now,

$\underline{\bf{Probability\:of\:not\:hitting\:boundary}}$ :

$\sf 1-P(E) \\ \\ \implies 1-0.2 \implies \boxed{\red{\bf{0.8}}}$

Cheers!

BrainlyPromoter Given,
Favourable outcomes = 6
Total balls = 30

Probability of favourable outcomes,
Favourable outcomes/Total Balls
6/30

On further dividing,
1/5 = 0.2

Now,
1 is always taken as a whole or total.

So,
Probability that she did not hit the boundary (unfavourable outcomes),
1 - Probability of favourable outcomes
1 - 0.2
1.0 - 0.2 = 0.8

There you go! That is your answer ;)

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