Answer:
51.95cm^2
Step-by-step explanation:
Area of arc=(angle/360)*pi*r^2
=(150/360)*22/7*6.3^2
=51.95cm^2
Given:
In the circle radius is 6.3cm
An arc subtends of angle measure 150°
To find:
Solution:
The radius of circle = 6.3cm
The angle of the arc = 150°
Length of the arc = Ф°/360° × (2πr)
Now, we will put the values and find the values
= 150/360 × 2 × [tex]\frac{22}{7}[/tex] × 6.3
= [tex]\frac{5}{12}[/tex] × 2 × [tex]\frac{22}{7}[/tex] × 6.3
= 16.5cm
Length of the arc = 17cm (approx)
2. Area of the sector formed by the arc.
Area of sector = Ф°/360° × πr²
= 150/360 ×[tex]\frac{22}{7}[/tex] × 6.3 × 6.3
= [tex]\frac{5}{12}[/tex] × [tex]\frac{22}{7}[/tex] × 6.3 × 6.3
= 51.97cm²
Area of the sector = 52cm²(approx)
Area of the sector formed by arc is 52cm².
Length of the arc = 17cm .
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Answers & Comments
Answer:
51.95cm^2
Step-by-step explanation:
Area of arc=(angle/360)*pi*r^2
=(150/360)*22/7*6.3^2
=51.95cm^2
Given:
In the circle radius is 6.3cm
An arc subtends of angle measure 150°
To find:
Solution:
The radius of circle = 6.3cm
The angle of the arc = 150°
Length of the arc = Ф°/360° × (2πr)
Now, we will put the values and find the values
= 150/360 × 2 × [tex]\frac{22}{7}[/tex] × 6.3
= [tex]\frac{5}{12}[/tex] × 2 × [tex]\frac{22}{7}[/tex] × 6.3
= 16.5cm
Length of the arc = 17cm (approx)
2. Area of the sector formed by the arc.
Area of sector = Ф°/360° × πr²
= 150/360 ×[tex]\frac{22}{7}[/tex] × 6.3 × 6.3
= [tex]\frac{5}{12}[/tex] × [tex]\frac{22}{7}[/tex] × 6.3 × 6.3
= 51.97cm²
Area of the sector = 52cm²(approx)
Area of the sector formed by arc is 52cm².
Length of the arc = 17cm .
Area of the sector formed by arc is 52cm².