In 100 gm of saturated solution, 36 gm of NaCl is present at 25°C.
(i)what will be the solubility ?
(ii)what will be the concentration ?
(iii) Calculate the amount of common salt to be dissolved in 1L of water at 25°C, to prepare saturated solution.
(i)what will be the solubility ?
(ii)what will be the concentration ?
(iii) Calculate the amount of common salt to be dissolved in 1L of water at 25°C, to prepare saturated solution.
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Answer:
(i)- 136gm
(ii)- 26.47%
Explanation:
(i)-solubility = solvent + solution=> 36+100= 136gm
(ii)-concentration = solvent × solution/ solubility
= 3600/136= 26.47%