I'm asking a difficult question and whosoever will answer this correct and accurate , I'll Mark it as brainliest and will also thank the answer Q- how we can make the electronic configuration of elements having atomic no 100 or more
For the elements whose atomic number is greater than 21, it will be easy if you calculate the electronic configuration of the sub-shells of that element and then calculate the electronic configuration of the shells.
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Explanation:
For elements of atomic number more than 20
Take an example of Iron which has atomic number 26
First calculate the electronic configuration of its sub- shells.
Fe(26): 1s2 2s2 2p6 3s2 3p6 4s2 3d6.
Then, calculate the electronic configuration of its shells.
Fe(26): 2 8 14 2.
EXCEPTION: Chromium (Atomic No.-24) and Copper (Atomic No.-29)
Cr(24): 1s2 2s2 2p6 3s2 3p6 4s1 3d5. Cr(24): 2 8 13 1
Cu(29): 1s2 2s2 2p6 3s2 3p6 4s1 3d10. Cu(29): 2 8 18 1.
For the elements whose atomic number is greater than 21, it will be easy if you calculate the electronic configuration of the sub-shells of that element and then calculate the electronic configuration of the shells.
By this way we can find it easily
Hope it helps
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