I.List two applications of concave mirror.
II.If the distance between the mirror and the principal focus is 15 cm, find the radius of curvature of the mirror.
III.Draw a ray diagram to show the type of image formed when an object is placed between the pole and focus of a concave mirror.
IV.An object 10 cm in size is placed at 100 cm in front of a concave mirror. If its image is formed at the same point where the object is located, find (i) focal length of the mirror, and (ii) magnification of the image formed with sign as per Cartesian sign convention.
Answers & Comments
ANSWER 1 Concave mirrors, also known as converging mirrors, are used in various applications in different fields. Here are two common applications of concave mirrors:
1. Reflecting telescopes: Concave mirrors are used in reflecting telescopes to collect and focus light from distant objects. The mirror is curved inward, which reflects and converges the light to a single point, where the image is formed. This type of telescope is widely used in astronomy and space exploration.
2. Headlights and searchlights: Concave mirrors are used in headlights and searchlights to produce a powerful beam of light. The bulb is placed at the focal point of the mirror, which reflects and converges the light to produce a highly intense beam of light. This type of mirror is also used in flashlights, torches, and other types of lighting devices.
ANSWER 2 The radius of curvature of a concave mirror is twice the distance between the mirror and the principal focus.
Given that the distance between the mirror and the principal focus is 15 cm, we can find the radius of curvature (R) as follows:
R = 2 x 15 cm = 30 cm
Therefore, the radius of curvature of the concave mirror is 30 cm.
ANSWER 3 The following ray diagram shows the formation of image by a concave mirror for an object placed between its pole and focus.
The image is formed behind the mirror when an object is placed between the focus F and the pole P
The three characteristics of the image are as follows :
DIAGRAM OF ANSWER THREE IN PIC
ANSWER 4 Sure, I can help you with that.
Given that the object is 10 cm in size and is placed at a distance of 100 cm in front of a concave mirror, and its image is formed at the same point where the object is located.
(i) To find the focal length of the mirror, we can use the mirror formula:
1/f = 1/v - 1/u
where f is the focal length of the mirror, v is the distance of the image from the mirror, and u is the distance of the object from the mirror.
Since the image is formed at the same point where the object is located, v = -u.
Substituting this value in the mirror formula, we get:
1/f = 1/-100 - 1/100
Simplifying, we get:
1/f = -2/100
1/f = -1/50
f = -50 cm
Therefore, the focal length of the concave mirror is -50 cm.
(ii) To find the magnification of the image formed, we can use the formula:
magnification (m) = height of the image (h') / height of the object (h)
Since the image formed is at the same point where the object is located, the distance of the object from the mirror is u = -100 cm and the distance of the image from the mirror is v = -100 cm.
The magnification can be calculated as follows:
m = h' / h = -v / u = -(-100) / (-100) = 1
Therefore, the magnification of the image formed is 1, which means that the image is the same size as the object and is neither magnified nor diminished.