Il Solve the following problems. Round off your answers to the nearest hundredths if possible. Show the solutions
1: Solve for area of kite whose diagonal length diagonal (d1) = 21.5 cm and diagonal (d2) = 15.8 cm.
2: Find the area of the kite with diagonals, diagonal (d1) = 26 cm and diagonal (d2) = 13 cm.
3: Two side length of kite is 7.8 cm and 11 cm. solve for perimeter of the kite.
4. The length of two adjacent sides of a kite are 1 m and 1 m 30 cm. Calculate the perimeter in cm.
5. If one length of a diagonal of a kite is 3 cm and its area be 7.5 cm2. Determine the length of other
diagonal.
6. Find the value of x. Using the figure below.
Answers & Comments
Answer:
1.
d1 d2
21.5 15.8
Area
S=d1×d22
S=21.50×15.802
S=339.702
S=169.85
Perimeter
P=2×√d12+d22
P=2×√21.502+15.802
P=2×√462.25+249.64
P=2×√711.89
P=2×26.68
P=53.36
a
a=√d12+d222
a=√21.502+15.8022
a=√462.25+249.642
a=√711.892
a=26.682
answer: a=13.34
2.
d1 d2
26 13
Area
S=d1×d22
S=26×132
S=3382
S=169
Perimeter
P=2×√d12+d22
P=2×√262+132
P=2×√676+169
P=2×√845
P=2×29.07
P=58.14
(a)
a=√d12+d222
a=√262+1322
a=√676+1692
a=√8452
a=29.072
answer: a=14.53
3.
d1 d2
7.8 11
Area
S=d1×d22
S=7.80×112
S=85.802
S=42.90
Perimeter
P=2×√d12+d22
P=2×√7.802+112
P=2×√60.84+121
P=2×√181.84
P=2×13.48
P=26.97
a
a=√d12+d222
a=√7.802+1122
a=√60.84+1212
a=√181.842
a=13.482
answer: a=6.74
4.
d1 d2
7.8 11
Area
S=d1×d22
S=7.80×112
S=85.802
S=42.90
Perimeter
P=2×√d12+d22
P=2×√7.802+112
P=2×√60.84+121
P=2×√181.84
P=2×13.48
P=26.97
a
a=√d12+d222
a=√7.802+1122
a=√60.84+1212
a=√181.842
a=13.482
answer: a=6.74
5.
d1 d2
1 30
Area
S=d1×d22
S=1×302
S=302
S=15
Perimeter
P=2×√d12+d22
P=2×√12+302
P=2×√1+900
P=2×√901
P=2×30.02
P=60.03
a
a=√d12+d222
a=√12+3022
a=√1+9002
a=√9012
a=30.022
answer: a=15.01
5.
d1 d2
3 7.5
Area
S=d1×d22
S=3×7.502
S=22.502
S=11.25
Perimeter
P=2×√d12+d22
P=2×√32+7.502
P=2×√9+56.25
P=2×√65.25
P=2×8.08
P=16.16
a
a=√d12+d222
a=√32+7.5022
a=√9+56.252
a=√65.252
a=8.082
answer: a=4.04
6.
4x-40
Area
S=d1×d22
S=4×402
S=1602
S=80
Perimeter
P=2×√d12+d22
P=2×√42+402
P=2×√16+1600
P=2×√1616
P=2×40.20
P=80.40
a
a=√d12+d222
a=√42+4022
a=√16+16002
a=√16162
a=40.202
answer: a=20.10
2(x+5)
Area
S=d1×d22
S=2×52
S=102
S=5
Perimeter
P=2×√d12+d22
P=2×√22+52
P=2×√4+25
P=2×√29
P=2×5.39
P=10.77
a
a=√d12+d222
a=√22+522
a=√4+252
a=√292
a=5.392
a=2.69