III. Read, analyze, and solve to find the area following the steps in solving word problems. (2pts each)
1. A square carpet, one side of which is 5 m.
2. A piece of rectangular land is 110 m long and 73 m wide.
3. A classroom 9 m by 9 m.
4. A window 4 feet by 2 feet.
5. A trapezoid-shaped piece of wood which bases measure 128 m, 92 m and its height is 40 m.
1. A square carpet, one side of which is 5 m.
2. A piece of rectangular land is 110 m long and 73 m wide.
3. A classroom 9 m by 9 m.
4. A window 4 feet by 2 feet.
5. A trapezoid-shaped piece of wood which bases measure 128 m, 92 m and its height is 40 m.
Answers & Comments
Answer:
To solve for the areas of the given figures, we can use the appropriate formulas for each shape.
1. Square Carpet:
Since a square has all sides equal, and one side is given as 5m, we can use the formula for the area of a square:
Area = side^2
Substituting the given value:
Area = 5m^2 = 25m^2
Therefore, the area of the square carpet is 25 square meters.
2. Rectangular Land:
To find the area of a rectangle, we can multiply the length by the width:
Area = length × width
Substituting the given values:
Area = 110m × 73m = 8030m^2
Therefore, the area of the rectangular land is 8030 square meters.
3. Classroom:
Again, to find the area of a rectangle, we multiply the length by the width:
Area = length × width
Substituting the given values:
Area = 9m × 9m = 81m^2
Therefore, the area of the classroom is 81 square meters.
4. Window:
The area of a rectangle is given by multiplying the length by the width:
Area = length × width
Substituting the given values (converting feet to square feet):
Area = 4ft × 2ft = 8ft^2
Therefore, the area of the window is 8 square feet.
5. Trapezoid-shaped Piece of Wood:
The formula for the area of a trapezoid is given by:
Area = (base1 + base2) × height / 2
Substituting the given values:
Area = (128m + 92m) × 40m / 2 = 220 × 40 / 2 = 4400m^2
Therefore, the area of the trapezoid-shaped piece of wood is 4400 square meters.