Linear Equations

Standard form of equation of a line is ax + by + c = 0. Here a, b, are the coefficients. x, y are the variables. c is the constant term. The values of x and y represent the coordinates of the point on the line.

Answers:

A.

see attachment

B.

5. m = 3 ; the line is going up

6. m = undefined ; the line extends infinitely

7. m = \frac{4}{5}

5

4

; the line is going up

8. m = 2 ; the line is going up

C.

9. m = 5 ; the line is going up

10. m = \frac{3}{5}

5

3

; the line is going up

11. m = -2 ; the line is going down

12. m = \frac{-4}{3}

3

−4

; the line is going down

Solutions:

A. see attachment

B.

5. (0,-3)(1,0)

m = \frac{y_2 - y_1}{x_2 - x_1}

x

2

−x

1

y

2

−y

1

m = \frac{0 - (-3)}{1 - 0}

1−0

0−(−3)

m = \frac{0 + 3}{1}

1

0+3

m = \frac{3}{1}

1

3

m = 3

6. (-3,0)(0,-3)

m = \frac{y_2 - y_1}{x_2 - x_1}

x

2

−x

1

y

2

−y

1

m = \frac{-3 - 0}{0 - 0}

0−0

−3−0

m = \frac{-3}{0}

0

−3

m = undefined

7. (5,0)(0,-4)

m = \frac{y_2 - y_1}{x_2 - x_1}

x

2

−x

1

y

2

−y

1

m = \frac{-4 - 0}{0 - 5}

0−5

−4−0

m = \frac{-4}{-5}

−5

−4

m = \frac{4}{5}

5

4

8. (2,0)(0,-4)

m = \frac{y_2 - y_1}{x_2 - x_1}

x

2

−x

1

y

2

−y

1

m = \frac{-4 - 0}{0 - 2}

0−2

−4−0

m = \frac{-4}{-2}

−2

−4

m = 2

C.

9. m = 5

10. m = \frac{3}{5}

5

3

11. m = -2

12. m = \frac{-4}{3}

3

−4

How to find the equation of the line: brainly.ph/question/6642349

#BrainlyEveryday

Answer:

1+1 = 0 then you multiply it by 10 so the answer is tara ML? Thanks sa points BTW