II. Solve the following problems. Show your complete solutions.
1.If each exterior angle measures 10°, how many sides does this polygon have?
2. What is the measure of each interior angle of a regular hexadecagon (16 sided polygon)?
3. Find the angles of a polygon which are given as; (x – 70) °, x°, (x – 5) °, (3x – 44) °and
(x + 15) °.
4. Find the sum of the interior angles of a 19-gon.
5.Solve for
1.If each exterior angle measures 10°, how many sides does this polygon have?
2. What is the measure of each interior angle of a regular hexadecagon (16 sided polygon)?
3. Find the angles of a polygon which are given as; (x – 70) °, x°, (x – 5) °, (3x – 44) °and
(x + 15) °.
4. Find the sum of the interior angles of a 19-gon.
5.Solve for
Answers & Comments
Answer:
1) 36 sides
2) 157.50
3) 92
4) 3060
5) asan po yung complete na tanong?
Step-by-step explanation:
1) measure of exterior angle = 360 / n where n is # of sides
given yung exterior angle na 10 so
10 = 360 / n
n = 360 / 10 = 36 sides
2) measure of interior angle = (n-2)*180/n
= (16-2)*180/16 = 157.50
3) add mo lang lahat yan so makukuha mo 7x-104 dba, eto yung sum ng interior angles
tapos equal yan sa sum ng interior angles ng isang pentagon (5 interior angles kasi so 5-sided polygon ang hinahanap mo)
use formula for sum of int angles = (n-2)*180 = (5-2) * 180 = 540
tapos magiging 7x-104 = 540
solve for x
4) sum ng interior angles ay (n-2)*180 so (19-2)*180