Answer:
Wyzant
PRECALCULUS
James B. asked • 01/11/20
Find the inverse of f informally . Verify that f(f ^ (- 1) * (x)) = x and f ^ (- 1) * (f(x)) = x f(x) = sqrt(x)
You are verifying f(x)= square root x
Follow1
Add comment
More
1 Expert Answer
By:
Kerri P. answered • 01/11/20
TUTOR 5 (375)
Certified Mathematics Teacher Grades 7-12
ABOUT THIS TUTOR ›
We are starting out with f(x) = √x. Note that this function has a domain of x ≥ 0 and range of y ≥ 0.
To find the inverse function, switch the x and y (f(x)) and re-solve for y:
x = √y square both sides
y = x2
f-1(x) = x2, however we need to consider the domain and range
Since the range of f(x) was restricted to y ≥ 0 that means that the domain of f-1(x) is restricted to x ≥ 0 as well.
So technically f-1(x) = x2, for x ≥ 0 (just the right half of the parabola)
Next, you are asked to use composition of functions to verify.
f(f-1(x)) = √(x2) = x when x ≥ 0
f-1(f(x)) = (√x)2 = x when x ≥ 0
Therefore, they are inverses on the restricted domain.
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
Wyzant
PRECALCULUS
James B. asked • 01/11/20
Find the inverse of f informally . Verify that f(f ^ (- 1) * (x)) = x and f ^ (- 1) * (f(x)) = x f(x) = sqrt(x)
You are verifying f(x)= square root x
Follow1
Add comment
More
1 Expert Answer
By:
Kerri P. answered • 01/11/20
TUTOR 5 (375)
Certified Mathematics Teacher Grades 7-12
ABOUT THIS TUTOR ›
We are starting out with f(x) = √x. Note that this function has a domain of x ≥ 0 and range of y ≥ 0.
To find the inverse function, switch the x and y (f(x)) and re-solve for y:
x = √y square both sides
y = x2
f-1(x) = x2, however we need to consider the domain and range
Since the range of f(x) was restricted to y ≥ 0 that means that the domain of f-1(x) is restricted to x ≥ 0 as well.
So technically f-1(x) = x2, for x ≥ 0 (just the right half of the parabola)
Next, you are asked to use composition of functions to verify.
f(f-1(x)) = √(x2) = x when x ≥ 0
f-1(f(x)) = (√x)2 = x when x ≥ 0
Therefore, they are inverses on the restricted domain.