HERE IS YOUR ANSWER
[tex]voume \: of \: sphere \: = \frac{4}{3} \pi {r}^{3} \\ \\ = \frac{4}{3} \pi \: 4.5 \times 4.5 \times 4.5 \\ \\ = 121.5\pi[/tex]
[tex]\rule{200pt}{4pt}[/tex]
[tex]\underline{\underline{\bf{Solution : -}}}[/tex]
Radius of the soccer ball : - 4.5 in.
To Find volume of the soccer ball ;
Formula used :
[tex]\:\:\:\:\:\:\:\:\:\:[/tex] [tex]\sf\implies{\dfrac{4}{3} πr³}[/tex]
[tex]\\[/tex]
[tex]\:\:\:\:\:\:\:\:\:\:[/tex] [tex]\implies\sf{{\dfrac{4}{3} π × 4.5³}}[/tex]
[tex]\:\:\:\:\:\:\:\:\:\:[/tex] [tex]\implies\sf{121.5}[/tex]
Hence , correct answer is Option (c) 121.5
Additional Information :-
[tex]\begin{gathered}\begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Square} = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Triangle} = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Parallelogram} = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Trapezium} = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered} \end{gathered} \end{gathered}\end{gathered} [/tex]
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Answers & Comments
HI MATE
HERE IS YOUR ANSWER
ATQ
we have to find volume of sphere (football) whose radius = 4.5 inches
so volume is
[tex]voume \: of \: sphere \: = \frac{4}{3} \pi {r}^{3} \\ \\ = \frac{4}{3} \pi \: 4.5 \times 4.5 \times 4.5 \\ \\ = 121.5\pi[/tex]
HOPE IT HELPS
THANKU
Verified answer
[tex]\rule{200pt}{4pt}[/tex]
[tex]\underline{\underline{\bf{Solution : -}}}[/tex]
Radius of the soccer ball : - 4.5 in.
To Find volume of the soccer ball ;
Formula used :
[tex]\:\:\:\:\:\:\:\:\:\:[/tex] [tex]\sf\implies{\dfrac{4}{3} πr³}[/tex]
[tex]\\[/tex]
[tex]\:\:\:\:\:\:\:\:\:\:[/tex] [tex]\implies\sf{{\dfrac{4}{3} π × 4.5³}}[/tex]
[tex]\\[/tex]
[tex]\:\:\:\:\:\:\:\:\:\:[/tex] [tex]\implies\sf{121.5}[/tex]
Hence , correct answer is Option (c) 121.5
[tex]\rule{200pt}{4pt}[/tex]
Additional Information :-
[tex]\begin{gathered}\begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Square} = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Triangle} = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Parallelogram} = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Trapezium} = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered} \end{gathered} \end{gathered}\end{gathered} [/tex]