Step-by-step explanation:
x + y - 1 =0
x + y = 1
Cubing both sides of the equation, we get
(x+y)³ = 1³
=> x³ + y³ + 3xy(x+y) = 1
=> x³ + y³ + 3xy(1) = 1
=> x³ + y³ + 3xy = 1
Hence, proved.
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Verified answer
Step-by-step explanation:
x + y - 1 =0
x + y = 1
Cubing both sides of the equation, we get
(x+y)³ = 1³
=> x³ + y³ + 3xy(x+y) = 1
=> x³ + y³ + 3xy(1) = 1
=> x³ + y³ + 3xy = 1
Hence, proved.