Answer:
Given (x−2) is a common factor of x2+ax+b and x2+cx+d
∴x=2 is a root of x2+ax+b=0 and x2+cx+d=0
∴4+2a+b=0,4+2c+d=0
⇒2a+b=2c+d
⇒2(c−a)=b−d
⇒c−ab−d=2
Step-by-step explanation:
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Answers & Comments
Answer:
Given (x−2) is a common factor of x2+ax+b and x2+cx+d
∴x=2 is a root of x2+ax+b=0 and x2+cx+d=0
∴4+2a+b=0,4+2c+d=0
⇒2a+b=2c+d
⇒2(c−a)=b−d
⇒c−ab−d=2
Step-by-step explanation:
this is