Answer:
answer should be
0
it can be wrong also
Step-by-step explanation:
Given equation is (x²+1)/x = 10/3
=> (x²/x)+(1/x) = 10/3
On squaring both sides then
=> [x+(1/x)]² = (10/3)²
=> x²+2(x)(1/x)+(1/x)² = 100/9
Since, (a+b)² = a²+2ab+b²
Where, a = x and b = 1/x
=> x²+2(x/x)+(1/x²) = 100/9
=> x²+(1/x²) +2 = 100/9
=> x²+(1/x²) = (100/9)-2
=> x²+(1/x²) = (100-18)/9
Now,
[x-(1/x)]² = x²+(1/x²)-2(x)(1/x)
Since, (a-b)² = a²-2ab+b²
=> [x-(1/x)]² = (82/9)-2(x/x)
=> [x-(1/x)]² = (82/9)-2(1)
=> [x-(1/x)]² = (82/9)-2
=> [x-(1/x)]² = (82-18)/9
=> [x-(1/x)]² = 64/9
=> x-(1/x)= √(64/9)
( since x > 0)
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Answers & Comments
Answer:
answer should be
0
it can be wrong also
Verified answer
Step-by-step explanation:
♦ Given ♦ :-
♦ To find ♦ :-
♦ Solution ♦ :-
Given equation is (x²+1)/x = 10/3
=> (x²/x)+(1/x) = 10/3
=> x+(1/x) = 10/3
On squaring both sides then
=> [x+(1/x)]² = (10/3)²
=> x²+2(x)(1/x)+(1/x)² = 100/9
Since, (a+b)² = a²+2ab+b²
Where, a = x and b = 1/x
=> x²+2(x/x)+(1/x²) = 100/9
=> x²+(1/x²) +2 = 100/9
=> x²+(1/x²) = (100/9)-2
=> x²+(1/x²) = (100-18)/9
=> x²+(1/x²) = 82/9
Now,
[x-(1/x)]² = x²+(1/x²)-2(x)(1/x)
Since, (a-b)² = a²-2ab+b²
=> [x-(1/x)]² = (82/9)-2(x/x)
=> [x-(1/x)]² = (82/9)-2(1)
=> [x-(1/x)]² = (82/9)-2
=> [x-(1/x)]² = (82-18)/9
=> [x-(1/x)]² = 64/9
=> x-(1/x)= √(64/9)
=> x-(1/x) = 8/3
( since x > 0)
Answer :-
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