Step-by-step explanation:
9x^2 +4y^2 = 97
xy = 6
Using identity (a+b)^2
(3x +2y)^2 = 9x^2 + 2×3x × 2y + 4y^2
9x^2 +4y^2 + 6xy
Putting the values :
97 + 6×6 = 97+36 = 133
(3x+2y)^2 = 133
This question has a problem either it will be 9x^2 + 16y^2 or we have to find 27x^3 + 8y^3 because in one case its coming 3x+2y whole and in cube 3x +4y hence the values arent be replaced. which is needed to find the other value
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Step-by-step explanation:
9x^2 +4y^2 = 97
xy = 6
Using identity (a+b)^2
(3x +2y)^2 = 9x^2 + 2×3x × 2y + 4y^2
9x^2 +4y^2 + 6xy
Putting the values :
97 + 6×6 = 97+36 = 133
(3x+2y)^2 = 133
This question has a problem either it will be 9x^2 + 16y^2 or we have to find 27x^3 + 8y^3 because in one case its coming 3x+2y whole and in cube 3x +4y hence the values arent be replaced. which is needed to find the other value