if x² + 14x + 45 = 0, what's the largest possible value of x?
#CarryOnLearning
(ノ^_^)ノ
Answer:
x²+ 9×+5×+45=0
×(x+9)+5(x+9)=0
(×+9)×(×+5)=0
×+9=0
×+5=0
×=-9
×=-5
solution: x1=-9,×2=-5
Step-by-step explanation:
sana makatulong po. Yan lang po alam ko
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if x² + 14x + 45 = 0, what's the largest possible value of x?
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#CarryOnLearning
(ノ^_^)ノ
Answer:
x²+ 9×+5×+45=0
×(x+9)+5(x+9)=0
(×+9)×(×+5)=0
×+9=0
×+5=0
×=-9
×=-5
solution: x1=-9,×2=-5
Step-by-step explanation:
sana makatulong po. Yan lang po alam ko