if X + 1 by X square + X + 1 whole square is equals to X + B by X square + X + 1 + c x + D by X square + X + 1 whole square then a + b + C + D is equals to
Let's simplify the given expression to find the values of A, B, C, and D:
\[
\frac{{X + 1}}{{(X^2 + X + 1)^2}} = \frac{{X + B}}{{X^2 + X + 1}} + \frac{{C \cdot X + D}}{{(X^2 + X + 1)^2}}
\]
To solve for A, B, C, and D, you can equate the numerators:
\[X + 1 = (X + B) \cdot (X^2 + X + 1) + (C \cdot X + D)\]
Now, you can expand and compare coefficients to find A, B, C, and D. Once you have these values, you can calculate \(a + b + C + D\). If you provide the coefficients after solving, I can help you with the final calculation.
Answers & Comments
Answer:
Let's simplify the given expression to find the values of A, B, C, and D:
\[
\frac{{X + 1}}{{(X^2 + X + 1)^2}} = \frac{{X + B}}{{X^2 + X + 1}} + \frac{{C \cdot X + D}}{{(X^2 + X + 1)^2}}
\]
To solve for A, B, C, and D, you can equate the numerators:
\[X + 1 = (X + B) \cdot (X^2 + X + 1) + (C \cdot X + D)\]
Now, you can expand and compare coefficients to find A, B, C, and D. Once you have these values, you can calculate \(a + b + C + D\). If you provide the coefficients after solving, I can help you with the final calculation.
Step-by-step explanation:
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