if width of hollow cylinder is 2 cm its internal diameter is 14 cm and height is 26 and both the ends of the cylinder open then find the total surface area of hollow cylinder
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Answer:
the total surface area=inner surface area+outer surface area+2(circular surface area)
Step-by-step explanation:
inner surface area=2× 22/7 × 14 ×26
=44×52
=2288
outer surface area=2 ×22/7 ×16×26
=2614 ⁶/7
circular surface area=2(outer circle area - inner circle area)
=2(π((r2)²-(r1)²)).
= 2π(16²-14²)
=2π(256-196)
=2×22/7×60
= 377 ⅐
total surface area=
2288+2614 ⁶/7 + 377⅐
=2288+2614+ ⁶/7 + 377+⅐
=2288+2614+ 377+1
=5280 cm²
hence the answer
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