If w= C(5,2), x= C(5,3), y= C(5,4), and z= C(5,5), and we are given 5 points on a plane of which no three are collinear, which expression gives the total number of polygons that can be drawn?
A. x+y
B. w+x+y
C. x+y+z
D. w+x+y+z
(SHOW YOUR SOLUTION PLEASE THANK YOU)
A. x+y
B. w+x+y
C. x+y+z
D. w+x+y+z
(SHOW YOUR SOLUTION PLEASE THANK YOU)
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three non-collinear
total of 5 points
1st point on non collinear
1st combination: C(5, 3)
2nd point on non collinear
2nd combination: C(5, 4)
3rd point on non collinear
3rd combination: C(5, 5)
add
C(5, 3) + C(5, 4) + C(5, 5)
x + y + z
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