Answer:
getting two heads:
Let E1 = event of getting 2 heads. Then,
E1 = {HH} and, therefore, n(E1) = 1.
Therefore, P(getting 2 heads) = P(E1) = n(E1)/n(S) = 1/4.
Step-by-step explanation:
please Mark brainliests if I really help you please please please
1/6 because one coun having provaibality of 1/3
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Answer:
getting two heads:
Let E1 = event of getting 2 heads. Then,
E1 = {HH} and, therefore, n(E1) = 1.
Therefore, P(getting 2 heads) = P(E1) = n(E1)/n(S) = 1/4.
Step-by-step explanation:
please Mark brainliests if I really help you please please please
Answer:
1/6 because one coun having provaibality of 1/3