Let the number be x and the smaller one will y. We know that Divided = Divisor × Quotient + Remainder.
When 3x is divided by y , We get 4 as Quotient and 3 as remainder.
Therefore, by using (i), we get
3x = 4y + 3 => 3x - 4y - 3 = 0
When 7y is divided by x . We get 5 as Quotient and 1 as remainder.
7y = 5x + 1 => 5x - 7y + 1 = 0
Solving equations (ii) and (iii), by cross-multiplication, we get
= =
= -1 , = -1
=> x = 25 and y = 18
Hence, The required numbers are 25 and 18.
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Answers & Comments
Hey mate,
Let the number be x and the smaller one will y. We know that Divided = Divisor × Quotient + Remainder.
When 3x is divided by y , We get 4 as Quotient and 3 as remainder.
Therefore, by using (i), we get
3x = 4y + 3 => 3x - 4y - 3 = 0
When 7y is divided by x . We get 5 as Quotient and 1 as remainder.
7y = 5x + 1 => 5x - 7y + 1 = 0
Solving equations (ii) and (iii), by cross-multiplication, we get
= =
= -1 , = -1
=> x = 25 and y = 18
Hence, The required numbers are 25 and 18.
Hope it helps...