Given:-
Initial volume of a gas at STP (V₁) = 52 m³
Initial pressure of a gas at STP (P₁) = 100 kPa (approx.)
Final Pressure of the gas (V₂) = 104 cm of Hg = 104 × 1.33 kPa = 138.32 kPa
We know that,
Boyle's law of gases states that at constant temperature, the pressure of a gas is inversely proportional to the volume.
i.e.,
⟹ PV = constant
⟹ (100)(52) = (138.32)(V₂)
⟹ 5200/138.32 = V₂
∴ The volume of the gas decreases to 37.5 m³.
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Answer:-
Given:-
Initial volume of a gas at STP (V₁) = 52 m³
Initial pressure of a gas at STP (P₁) = 100 kPa (approx.)
Final Pressure of the gas (V₂) = 104 cm of Hg = 104 × 1.33 kPa = 138.32 kPa
We know that,
Boyle's law of gases states that at constant temperature, the pressure of a gas is inversely proportional to the volume.
i.e.,
⟹ P ∝ 1/V
⟹ PV = constant
⟹ P₁V₁ = P₂V₂
⟹ (100)(52) = (138.32)(V₂)
⟹ 5200/138.32 = V₂
⟹ 37.5 m³ = V₂
∴ The volume of the gas decreases to 37.5 m³.