Answer:
Given sinθ=1/3⟹cosecθ=3
2cot2θ+2=2(1+cot2θ)=2cosec2θ=2(9)=18
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Answer:
Given sinθ=1/3⟹cosecθ=3
2cot2θ+2=2(1+cot2θ)=2cosec2θ=2(9)=18