Answer:
Explanation:
A+B).(A-B) =( A+B)(A-B)cos90
A^2 - B^2 = 0
A/B =1
so ans is 1
Or
Given that
A and B are two vector
A+B and A-B are perpendicular to each other.
We know that if two vectors(M and N) are perpendicular to each other then
M . N = |M|. |N| cos θ
Perpendicular θ =90°
so cos 90° = 0
M . N = |M|. |N| cos θ = |M|. |N| x 0
M . N = 0
So we can say that
( A+B ).(A-B ) = 0
A.A+B.A- A.B - B.B = 0 ( A.B=B.A)
A.A - B.B=0
|A| = |B|
So ratio of their magnitude is 1.
____/\___☺️
Hope it may helps you
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Answers & Comments
Answer:
Explanation:
A+B).(A-B) =( A+B)(A-B)cos90
A^2 - B^2 = 0
A/B =1
so ans is 1
Or
Given that
A and B are two vector
A+B and A-B are perpendicular to each other.
We know that if two vectors(M and N) are perpendicular to each other then
M . N = |M|. |N| cos θ
Perpendicular θ =90°
so cos 90° = 0
M . N = |M|. |N| cos θ = |M|. |N| x 0
M . N = 0
So we can say that
( A+B ).(A-B ) = 0
A.A+B.A- A.B - B.B = 0 ( A.B=B.A)
A.A - B.B=0
So we can say that
|A| = |B|
So ratio of their magnitude is 1.
____/\___☺️
Hope it may helps you