Answer:

(1) 4n + 3

(2) 4n + 5

(3) 4n + 6

(4) 4n + 7

Solution:

Sn = 2n2 + 5n

S1 = 2+5 = 7

First term = 7

S2 = 2×22 + 5×2 = 8+10 = 18

Second term = 18-7 = 11

Common difference, d = 11-7 = 4

Nth term = a+(n-1)d

= 7+(n-1)4

= 7+4n-4

= 4n+3

Hence option (1) is the answer.