Answer:

Sp=2p×[2a+(p−1)d]=q........(i)Sq=2q×[2a+(q−1)d]=p........(ii)Sp+q=2p+q×[2a+(p+q−1)d]

From equation (i) and (ii), we get,

2p×[2a+(p−1)d]=q=>2a+(p−1)d=p2q........(iii)and2q×[2a+(q−1)d]=p=>2a+(q−1)d=q2p........(iv)

Subtracting (iii) and (iv), we get,

q2p−p2q=(q−p)d=>pq2(p+q)(p−q

~ Priyanshu

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