If the sides of quadiletral are 37.6, 33, 35, 35.6 (all are in meter).
Find the area of quadiletral.
Is it possible to draw a unique quadiletral when all sides are given?
Find the area of quadiletral.
Is it possible to draw a unique quadiletral when all sides are given?
Answers & Comments
Answer:
Consider ABCD is a quadrilateral where,
AB=12,BC=5,CD=6,DA=15 and ∠ABC=90o
Area of ABCD= Area of ΔABC+Area of ΔACD
In Δ ABC, ∠B=90o
Apply Pythagoras theorem in ΔABC
Therefore, AC2=AB2+BC2=122+52
So, AC=13
Area of ΔABC=21×AB×BC=21×12×5=30m2
In ΔACD, let s be the semiperimeter,
S=26+15+13=17m
Applying Heron's formula,
Area of ΔACD = S(S−a)(S−b)(S−c) = 17(17−13)(17−15)(17−6)
= 17(4)(2)(11)=2374
Hence, Area of quadrilateral ABCD=
30+2374
Answer:Height of the pole is 21.13 m.Step-by-step explanation:Let EC be the tower of height 50 m and AB is the pole of height h.