Step-by-step explanation:
LCM X HCF = N1 X N2
60 x hcf = n1 x n2
let hcf of two nos be x
and ratio of n1 and n2 is 3:4
so
60 x x = 3x x 4x
(3x and 4x because both are in ratio 3:4 and x is their highest common factor that is the only number other that can be taken out common when they are divided to leave 3:4 ratio)
60x x = 12(x^2)
60 = 12x
x = 5
hence number 1 is 5x3 = 15
and number 2 is 5x4 = 20
the numbers are 15 and 20
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Verified answer
Step-by-step explanation:
LCM X HCF = N1 X N2
60 x hcf = n1 x n2
let hcf of two nos be x
and ratio of n1 and n2 is 3:4
so
60 x x = 3x x 4x
(3x and 4x because both are in ratio 3:4 and x is their highest common factor that is the only number other that can be taken out common when they are divided to leave 3:4 ratio)
60x x = 12(x^2)
60 = 12x
x = 5
hence number 1 is 5x3 = 15
and number 2 is 5x4 = 20
the numbers are 15 and 20