where,
Given that,
So,
Slant height of frustum is
Now,
We know,
Answer:
Given: Radii (r ) = 14 cm, and (r ) = 6 cm, height (h) = 6 cm Slant height of frustum (l) i. Curved surface area of frustum = πl (r1 + r2 ) = 3.14 × 10(14 + 6) = 3.14 × 10 × 20 = 628 cm2 ∴ The curved surface area of the frustum is 628 cm2 . ii. Total surface area of frustum = πl (r1 + r2 ) + πr12 + πr22 = 628 + 3.14 × (14)2 + 3.14 × (6)2 = 628 + 3.14 × 196 + 3.14 × 36 = 628 + 3.14(196 + 36) = 628 + 3.14 × 232 = 628 + 728.48 = 1356.48 cm2 ∴ The total surface area of the frustum is 1356.48 cm2. iii. Volume of frustum = 1/3 πth(r12 +r22 + r1 × r2 ) = 1/3 × 3.14 × 6(142 + 62 + 14 × 6) = 3.14 × 2(196 + 36 + 84) = 3.14 × 2 × 316 = 1984.48 cm3 ∴ The volume of the frustum is 1984.48 cm3.
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Answers & Comments
Given :-
To Find :-
Formula Used :-
where,
Solution :-
Given that,
So,
Slant height of frustum is
Hence,
Now,
We know,
Verified answer
Answer:
Given: Radii (r ) = 14 cm, and (r ) = 6 cm, height (h) = 6 cm Slant height of frustum (l) i. Curved surface area of frustum = πl (r1 + r2 ) = 3.14 × 10(14 + 6) = 3.14 × 10 × 20 = 628 cm2 ∴ The curved surface area of the frustum is 628 cm2 . ii. Total surface area of frustum = πl (r1 + r2 ) + πr12 + πr22 = 628 + 3.14 × (14)2 + 3.14 × (6)2 = 628 + 3.14 × 196 + 3.14 × 36 = 628 + 3.14(196 + 36) = 628 + 3.14 × 232 = 628 + 728.48 = 1356.48 cm2 ∴ The total surface area of the frustum is 1356.48 cm2. iii. Volume of frustum = 1/3 πth(r12 +r22 + r1 × r2 ) = 1/3 × 3.14 × 6(142 + 62 + 14 × 6) = 3.14 × 2(196 + 36 + 84) = 3.14 × 2 × 316 = 1984.48 cm3 ∴ The volume of the frustum is 1984.48 cm3.