If the potential difference generated by a battery across a circuit of two bulbs, combined in
series, is 6 volts, and the potential difference at the first bulb is 2 volts, find out the potential
difference at the second bulb?
series, is 6 volts, and the potential difference at the first bulb is 2 volts, find out the potential
difference at the second bulb?
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:-) 6=2+V2
:-) V2=4
Hence, potential difference at second bulb is 4V
Explanation:
In series, total V=V1+ V2
:-) 6=2+V2
:-) V2=4
Hence, potential difference at second bulb is 4V