[tex] \sf \: Perimerer_{(Rectangle)}=2(l+b)[/tex]
[tex] \sf \: Perimerer_{(Rectangle)}=2(30+b) = 90[/tex]
[tex] \sf \: Perimerer_{(Rectangle)}= 45=b + 30[/tex]
[tex] \sf \: Perimerer_{(Rectangle)} = b = 45 - 30[/tex]
[tex] \sf \: Perimerer_{(Rectangle)} = \red{b = 15}[/tex]
[tex] \sf \: Perimerer_{(Rectangle)}=2(30+15)[/tex]
[tex] \sf \: Perimerer_{(Rectangle)}=90[/tex]
Answer:
As we know
According To Question
Hence,Breadth is 15m.
✅Verification✨
Hence Verified✅
Step-by-step explanation:
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Answers & Comments
As we know
[tex] \sf \: Perimerer_{(Rectangle)}=2(l+b)[/tex]
According To Question
[tex] \sf \: Perimerer_{(Rectangle)}=2(30+b) = 90[/tex]
[tex] \sf \: Perimerer_{(Rectangle)}=2(30+b) = 90[/tex]
[tex] \sf \: Perimerer_{(Rectangle)}= 45=b + 30[/tex]
[tex] \sf \: Perimerer_{(Rectangle)} = b = 45 - 30[/tex]
[tex] \sf \: Perimerer_{(Rectangle)} = \red{b = 15}[/tex]
Hence,Breadth is 15m.
✅Verification✨
[tex] \sf \: Perimerer_{(Rectangle)}=2(l+b)[/tex]
[tex] \sf \: Perimerer_{(Rectangle)}=2(30+15)[/tex]
[tex] \sf \: Perimerer_{(Rectangle)}=90[/tex]
Hence Verified✅
Answer:
As we know
According To Question
Hence,Breadth is 15m.
✅Verification✨
Hence Verified✅
Step-by-step explanation: