Step-by-step explanation:
x Frequency fx
3 6 18
5 8 40
7 15 105
9 p 9p
11 8 88
13 4 52
41 + p 303 + 9p
Mean = (303 + 9p)/(41 + p) = 8
=> 303 + 9p = 328 + 8p
=> p = 25
Learn more:
The mean of x-5y,x-3y,xy,x+y,x+3y and x+5y is 12 then vakue if x is
brainly.in/question/7309600
Given the mean of the following data is 53, find the value of x and y ...
brainly.in/question/10374934
The value of p is 105.
x 3 5 7 9 11 13
f 6 8 15 p 8 4
mean =
Now , we evaluate = 18+40+105+9p+88+52 = 303+9p
Now, = 6+8+15+p+8+4 = 41+p
Substituting values , we get
8 = =
328 +8p = 303+9p
p = 25
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Answers & Comments
p = 25 if the mean of the following frequency distribution is 8 x 3,5,7,9,11,13 f 6,8,15,p,8 ,4
Step-by-step explanation:
x Frequency fx
3 6 18
5 8 40
7 15 105
9 p 9p
11 8 88
13 4 52
41 + p 303 + 9p
Mean = (303 + 9p)/(41 + p) = 8
=> 303 + 9p = 328 + 8p
=> p = 25
Learn more:
The mean of x-5y,x-3y,xy,x+y,x+3y and x+5y is 12 then vakue if x is
brainly.in/question/7309600
Given the mean of the following data is 53, find the value of x and y ...
brainly.in/question/10374934
The value of p is 105.
x 3 5 7 9 11 13
f 6 8 15 p 8 4
mean =![\frac{\sum f_i.x_i}{\sum x_i} \frac{\sum f_i.x_i}{\sum x_i}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csum%20f_i.x_i%7D%7B%5Csum%20x_i%7D)
Now , we evaluate
= 18+40+105+9p+88+52 = 303+9p
Now,
= 6+8+15+p+8+4 = 41+p
Substituting values , we get
8 =
= ![\frac{223+9p}{41+p} \frac{223+9p}{41+p}](https://tex.z-dn.net/?f=%5Cfrac%7B223%2B9p%7D%7B41%2Bp%7D)
328 +8p = 303+9p
p = 25