[tex]\sf{\large{ \mathfrak{\red{\underline{Given :}}}}} \\ [/tex]
━━━━━━━━━━━━━━━━━━━━━━
[tex]\sf{\large{ \mathfrak{\red{\underline{To \: find :}}}}} \\ [/tex]
[tex] \sf{\large{ \mathfrak{\red{\underline{Solution :}}}}} \\ [/tex]
We know that,
[tex] ▪\: \: m = \frac{h_{2}}{h_{1}} \\ [/tex]
By substituting the given values in the above formula, we get ;
[tex] \implies 2 = \frac{h_{2}}{1} \\ [/tex]
[tex] \implies h_{2} = 2 \\ [/tex]
∴ The size of the image is [tex] \boxed{\red{\underline{\bm {2m}}}}. \\ [/tex]
Hope it helped you...
Thank you !!!
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[tex]\sf{\large{ \mathfrak{\red{\underline{Given :}}}}} \\ [/tex]
━━━━━━━━━━━━━━━━━━━━━━
[tex]\sf{\large{ \mathfrak{\red{\underline{To \: find :}}}}} \\ [/tex]
━━━━━━━━━━━━━━━━━━━━━━
[tex] \sf{\large{ \mathfrak{\red{\underline{Solution :}}}}} \\ [/tex]
We know that,
[tex] ▪\: \: m = \frac{h_{2}}{h_{1}} \\ [/tex]
By substituting the given values in the above formula, we get ;
[tex] \implies 2 = \frac{h_{2}}{1} \\ [/tex]
[tex] \implies h_{2} = 2 \\ [/tex]
∴ The size of the image is [tex] \boxed{\red{\underline{\bm {2m}}}}. \\ [/tex]
━━━━━━━━━━━━━━━━━━━━━━
Hope it helped you...
Thank you !!!