here is your answer
Let the length of old rectangle = l
Let the breadth of old rectangle = b
Perimeter of the old rectangle = 2(length + breadth) = 2(l + b)
When the length and the breadth of the rectangle are doubled, then
length of the new rectangle = 2l
breadth of the new rectangle = 2b
∴ Perimeter of new rectangle = 2(length + breadth)
= 2(2l + 2b)
= 2 × 2(l + b)
= 2 × perimeter of the old rectangle [∵ perimeter of old rectangle = 2(l + b)]
Hence, the perimeter of the new rectangle will become two times of the perimeter of the old rectangle.
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Answers & Comments
here is your answer
Let the length of old rectangle = l
Let the breadth of old rectangle = b
Perimeter of the old rectangle = 2(length + breadth) = 2(l + b)
When the length and the breadth of the rectangle are doubled, then
length of the new rectangle = 2l
breadth of the new rectangle = 2b
∴ Perimeter of new rectangle = 2(length + breadth)
= 2(2l + 2b)
= 2 × 2(l + b)
= 2 × perimeter of the old rectangle [∵ perimeter of old rectangle = 2(l + b)]
Hence, the perimeter of the new rectangle will become two times of the perimeter of the old rectangle.
pls mark me as brainliest