Answer:
use formula an= a+(n-1)d
where a is the first term
d= common difference
an = nth term
this formula for finding A P
for sum of n terms= sn = a(n/2+1)d
The common difference of the AP is 4.
Explanation:
As per given , we have
last term= 119
8th term from the end =91
Since the AP is starting from the end , let a = 119 and d= common difference for the given arithmetic progression from the end.
Since nth term = a+(n-1)d
It means 8th term from the end : 119+(8-1)d= 91119+(8−1)d=91
\begin{gathered}119+7d=91\\\\ 7d= 91-119\\\\ 7d= -28\\\\ d=\dfrac{-28}{7}=-4\end{gathered}
119+7d=91
7d=91−119
7d=−28
d=
7
−28
=−4
Now , the common difference of the AP is -d = -(-4) = 4
Hence, the common difference of the AP is 4.
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Answers & Comments
Answer:
use formula an= a+(n-1)d
where a is the first term
d= common difference
an = nth term
this formula for finding A P
for sum of n terms= sn = a(n/2+1)d
Verified answer
The common difference of the AP is 4.
Explanation:
As per given , we have
last term= 119
8th term from the end =91
Since the AP is starting from the end , let a = 119 and d= common difference for the given arithmetic progression from the end.
Since nth term = a+(n-1)d
It means 8th term from the end : 119+(8-1)d= 91119+(8−1)d=91
\begin{gathered}119+7d=91\\\\ 7d= 91-119\\\\ 7d= -28\\\\ d=\dfrac{-28}{7}=-4\end{gathered}
119+7d=91
7d=91−119
7d=−28
d=
7
−28
=−4
Now , the common difference of the AP is -d = -(-4) = 4
Hence, the common difference of the AP is 4.