Answer:

Correct option is A)

f(x)=x

3

+e

x/2

f

′

(x)=3x

2

+

2

1

e

x/2

Given g is inverse of f ⇒g(f(x))=x

Differentiating both sides w.r.t x

g

′

(f(x)).f

′

(x)=1⇒g

′

(f(x))=

f

′

(x)

1

Clearly f

′

(0)=1∴g

′

(1)=g

′

(f(0))= f ′

(0)1

me=2

Answer:

Step-by-step explanation:

g=f

−1

f(g(x))=x

Differentiate w.r.t.x

f

′

(g(x))⋅g

′

(x)=1

∴

1+(g(x))

4

1

​

⋅g

′

(x)=1

g

′

(x)=1+[g(x)]

4

Hope it helped! please mark me the brainliest!!