Answer:
210cm²
Step-by-step explanation:
area of triangle = 1/2 * base * height
= 1/2 *21*20 = 210cm²
Area of triangle = ½× base × height
½ × 21 × 20
= 1 × 21 × 10
= 210cm²
Thus , Area of triangle is 210 cm²
__________________________________________________________________________
Area of equilateral triangle
[tex] \sf \: \frac{ \sqrt{3} }{4} \times {s}^{2} [/tex]
Area of triangle
[tex] \sf\frac{1}{2} \times b \times h[/tex]
if 3 side given,
[tex] \sf \sqrt{s(s - a)(s - b)(s - c)} [/tex]
abc is side .
[tex] \sf \: side \: = \frac{a + b + c}{2} [/tex]
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
210cm²
Step-by-step explanation:
area of triangle = 1/2 * base * height
= 1/2 *21*20 = 210cm²
Verified answer
Required Answer :-
Given :-
To find :-
By Using:-
Area of triangle = ½× base × height
Solution
Area of triangle = ½× base × height
½ × 21 × 20
= 1 × 21 × 10
= 210cm²
Thus , Area of triangle is 210 cm²
__________________________________________________________________________
More Information
Area of equilateral triangle
[tex] \sf \: \frac{ \sqrt{3} }{4} \times {s}^{2} [/tex]
Area of triangle
[tex] \sf\frac{1}{2} \times b \times h[/tex]
if 3 side given,
[tex] \sf \sqrt{s(s - a)(s - b)(s - c)} [/tex]
abc is side .
[tex] \sf \: side \: = \frac{a + b + c}{2} [/tex]