Answer:
Step 1: Write the balanced chemical equation for the reaction.
Step 2: Calculate the moles of "given" substance. If more than one reactant amount is given,
calculate the moles of each to determine which is the limiting reactant.
Step 3: Calculate the moles of "desired" substance from your answer in Step 2 using the coefficients
from the balanced chemical equation. If more than one reactant was given originally, you can
calculate the moles of product twice, based on the moles of each reactant. The reactant that
gives the smaller moles of product is the limiting reactant. Keep this answer for Step 4.
Step 4: Convert your answer in Step 3 to the units the problem asks for. Usually this is grams, but it
could be volume (for gases or liquid solutions) or concentration (such as molarity, for
solutions).
Again, in brief:
1. Balanced reaction.
2. Moles of "given" substance(s).
3. Moles of "desired" substance such as a product.
4. Convert Step 3 answer to the units asked for.
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
Step 1: Write the balanced chemical equation for the reaction.
Step 2: Calculate the moles of "given" substance. If more than one reactant amount is given,
calculate the moles of each to determine which is the limiting reactant.
Step 3: Calculate the moles of "desired" substance from your answer in Step 2 using the coefficients
from the balanced chemical equation. If more than one reactant was given originally, you can
calculate the moles of product twice, based on the moles of each reactant. The reactant that
gives the smaller moles of product is the limiting reactant. Keep this answer for Step 4.
Step 4: Convert your answer in Step 3 to the units the problem asks for. Usually this is grams, but it
could be volume (for gases or liquid solutions) or concentration (such as molarity, for
solutions).
Again, in brief:
1. Balanced reaction.
2. Moles of "given" substance(s).
3. Moles of "desired" substance such as a product.
4. Convert Step 3 answer to the units asked for.