We have, sinθ+cosθ=1

Multiplying both sides by

2

1

, we get

2

1

sinθ+

2

1

cosθ=

2

1

⟹sinθcos

4

π

+cosθsin

4

π

=sin

4

π

⟹sin(θ+

4

π

)=sin

4

π

General solution:

⟹θ+

4

π

=nπ+(−1)

n

4

π

⟹θ=nπ+(−1)

n

4

π

−

4

π

⟹θ=nπ+{(−1)

n

−1}

4

π

,n=0,±1,±2

me 9th class me padha ti hun dear and your intro