Verified answer

[tex] \huge\colorbox{blue}{ \color{white}{ANSWER}}[/tex]

The estimated correct question is

[tex] If \ sin(A + B) = 1 \ and \ sin(A – B) = \frac{1}{2} , 0 ≤ A + B ≤ 90° \ and \ A > B \ then \ find \ A \ and \ B  [/tex]

So the answer will be like this

[tex] sin(A + B) = 1 = sin90° \\ \therefore A+B =90° \\ and \ sin(A-B) = \frac{1}{2} = sin30° \\ \therefore A-B = 30° \\ from \ (i) + (ii) \ we \ will \ get, \\ A+B + A - B = 90° + 30° \\ \implies 2A = 120°\\ \implies A = 60°  [/tex]

now by putting A = 60° in the first equation we get, [tex] 60° + B = 90° \\ \implies B = 90°-60° = 30° [/tex]

[tex] \small\color{green}{✨hope \ you \ found \ my \ answer \ helpful. ✨}[/tex]