Answer:

We know that foot of perpendicular from (�1,�1)(x1,y1) on straight line ax + by + c = 0(�1,�1)(x1,y1)

is (h,k) then:

ℎ−�1�=�−�1�=−��1+��1+��2+�2ah−x1=bk−y1=−a2+b2ax1+by1+c

Explanation:

We know that foot of perpendicular from (�1,�1)(x1,y1) on line ax + by + c = 0

Formula is :

�−�1�=�−�1�=−��1+��1+��2+�2ax−x1=by−y1=−a2+b2ax1+by1+c

where (x,y) is foot of perpendicular of (�1,�1)(x1,y1) from ax + by + c = 0

So here in question given to us is foot of perpendicular is (h,k) and we nedd to prove formula.

Putting value of of point(h,k) in question,

ℎ−�1�=�−�1�=−��1+��1+��2+�2ah−x1=bk−y1=−a2+b2ax1+by1+c

Hence proved