Given, p(x) = 2x³ – 3x² + 5x – 4
x – 2 = 0
⇒ x = 2
By remainder theorem, when p(x) is divided by (x – 2), the remainder = p(2).
∴ p(2) = 2(2)³ – 3(2)² + 5 × 2 – 4
= 2 × 8 – 3 × 4 + 10 – 4
= 16 – 12 + 10 – 4
= 10
When p(x) is divided by (x – 2), the remainder is 10.
Answer:
remainder is 10
Step-by-step explanation:
to both of u
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Solution:
Given, p(x) = 2x³ – 3x² + 5x – 4
x – 2 = 0
⇒ x = 2
By remainder theorem, when p(x) is divided by (x – 2), the remainder = p(2).
∴ p(2) = 2(2)³ – 3(2)² + 5 × 2 – 4
= 2 × 8 – 3 × 4 + 10 – 4
= 16 – 12 + 10 – 4
= 10
Answer:
When p(x) is divided by (x – 2), the remainder is 10.
Verified answer
Answer:
remainder is 10
Step-by-step explanation:
to both of u