If three points are collinear then area of triangle will be 0
[1/2(x1(y2-y3) +X2(y3-y1)+X3(y1-y2)] = 0
[1/2(x(1-5)+2(5-(-1)+4(-1-1)] = 0
[1/2(x(-4)+2(6)+4(-2)] = 0
[1/2 (-4x+12-8)] = 0
-4x+4 = 0
-4x = -4
x = -4/-4 = 1
thus the value of x is 1
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If three points are collinear then area of triangle will be 0
[1/2(x1(y2-y3) +X2(y3-y1)+X3(y1-y2)] = 0
[1/2(x(1-5)+2(5-(-1)+4(-1-1)] = 0
[1/2(x(-4)+2(6)+4(-2)] = 0
[1/2 (-4x+12-8)] = 0
-4x+4 = 0
-4x = -4
x = -4/-4 = 1
thus the value of x is 1