If one zero of the polynomial p(x) = x² + 11x + k is -3, the value of k is p(x) = x + 11x + k বহুপদৰ এটা শূন্য – 3 হলে, k ৰ মান হ’ব— a) 20 b) 24 c) 40 d) 42
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Step-by-step explanation:
Given equation :- x² + 11x + k
It is given that -3 is the zeros of the given Equation !!
So, if we put the value of x as -3 we get Zero as resultant.
Answers & Comments
Answer:
When one zero of a polynomial p(x) is known, it can be used to find the value of the constant term, k.
Given that one zero of the polynomial p(x) = x² + 11x + k is -3, we can use this zero to find the value of k.
A polynomial p(x) = ax² + bx + c has the zero -3 if and only if p(-3) = 0
so,
p(-3) = (-3)² + 11*(-3) + k = 9 - 33 + k = -24 + k = 0
so k = 24
Therefore the value of k is 24. So the answer is b) 24
Answer:
Hello my Friend! i know you are in need of help therefore i had wrote the answer for you. If u seem the answer is incorrect then i am really sorry for that. If u seem the answer is well then well in good. please mark me as brainliest as it took me some minutes to do it. And i hope you have a great day buddy! Please help me in my question as well man. Okay! Bye bye! Have a nice day
Step-by-step explanation:
Given equation :- x² + 11x + k
It is given that -3 is the zeros of the given Equation !!
So, if we put the value of x as -3 we get Zero as resultant.
=>
x² + 11x + k = 0
( - 3 )² + 11 × ( - 3 ) + k = 0
9 - 33 + k = 0
- 24 + k = 0
k = 24 !!
So , the value of k as 24 will give
x = ( - 3 )