Answer:
kx2 – 5x + 2 = 0
Comparing with ax2 + bx + c = 0 we have a = k, b = – 5, c = 2
Let α and β be the roots of given quadratic equation.
α = 4 β [Given]
∴ α +β = - b/a = - (- 5)/k = 5/k
∴ 4β + β = 5/k
∴ 5β = 5/k
∴ β = 5/5k
∴ β = 1/k
Also, α.β = c/a = 2/k
∴ 4β .β = 2/k
∴ 4(1/k)(1/k) = 2/k
∴ 4/k2 = 2/k
∴ 4/2 = k2/k
∴ 2 = k
Now decode the following on Base 64 decoder :
SGVsbG8gYWRpdHlhc2hhdzAyIGlzIG15IEluc3RhZ3JhbS4gRm9sbG93IG1lIHRoZXJlLg==
Hint : Copy the above code and then search base 64 decoder on chrome or any browser. Then paste that code.
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Verified answer
Answer:
kx2 – 5x + 2 = 0
Comparing with ax2 + bx + c = 0 we have a = k, b = – 5, c = 2
Let α and β be the roots of given quadratic equation.
α = 4 β [Given]
∴ α +β = - b/a = - (- 5)/k = 5/k
∴ 4β + β = 5/k
∴ 5β = 5/k
∴ β = 5/5k
∴ β = 1/k
Also, α.β = c/a = 2/k
∴ 4β .β = 2/k
∴ 4(1/k)(1/k) = 2/k
∴ 4/k2 = 2/k
∴ 4/2 = k2/k
∴ 2 = k
Now decode the following on Base 64 decoder :
SGVsbG8gYWRpdHlhc2hhdzAyIGlzIG15IEluc3RhZ3JhbS4gRm9sbG93IG1lIHRoZXJlLg==
Hint : Copy the above code and then search base 64 decoder on chrome or any browser. Then paste that code.