[tex](ANSWER)[/tex]
To find the value of log(2) * sqrt^x 2, we can use the properties of logarithms.
First, let's rewrite the given equation log(sqrt^x 2) = a in exponential form:
sqrt^x 2 = 10^a
Now, let's rewrite log(2) * sqrt^x 2 using the exponential form:
log(2) * sqrt^x 2 = log(2) * (10^a)
Using the property of logarithms that states log(b^k) = k * log(b), we can simplify further:
log(2) * (10^a) = log(2) * 10^a
Now, we need to evaluate log(2) * 10^a. Since log(2) is a constant, we can multiply it by 10^a to get the final result.
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[tex](ANSWER)[/tex]
To find the value of log(2) * sqrt^x 2, we can use the properties of logarithms.
First, let's rewrite the given equation log(sqrt^x 2) = a in exponential form:
sqrt^x 2 = 10^a
Now, let's rewrite log(2) * sqrt^x 2 using the exponential form:
log(2) * sqrt^x 2 = log(2) * (10^a)
Using the property of logarithms that states log(b^k) = k * log(b), we can simplify further:
log(2) * (10^a) = log(2) * 10^a
Now, we need to evaluate log(2) * 10^a. Since log(2) is a constant, we can multiply it by 10^a to get the final result.
HOPE ITS HELP YOU