Answer:
Given □ABCD is cyclic and ∠B=110
∘
In a cyclic quadrilateral the sum of opposite angles=180
⇒∠A+∠C=180
⇒∠B+∠D=180
⇒110
+∠D=180
⇒∠D=180
−110
⇒∠D=70
Given ABCD is cyclic and <B=110
O
→ ZA+ZC=180
→ <B+ZD=180
⇒ 110
GIV+ZD=180
⇒ 4D=180
-110
⇒ <D=70
hope it helps ☺️
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Answers & Comments
Answer:
Given □ABCD is cyclic and ∠B=110
∘
In a cyclic quadrilateral the sum of opposite angles=180
∘
⇒∠A+∠C=180
∘
⇒∠B+∠D=180
∘
⇒110
∘
+∠D=180
∘
⇒∠D=180
∘
−110
∘
⇒∠D=70
∘
Given ABCD is cyclic and <B=110
O
In a cyclic quadrilateral the sum of opposite angles=180
O
→ ZA+ZC=180
→ <B+ZD=180
⇒ 110
GIV+ZD=180
⇒ 4D=180
O
-110
O
⇒ <D=70
hope it helps ☺️