Verified answer

Step-by-step explanation:

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Step-by-step explanation:

♦ Given ♦ :-

• f(x) and g(x) be the two functions defined by f(x)=3x²-2x+1, g(x)=2x²-3x+7 .

• f(x)=g(x)

♦ To find ♦ :-

• The value of x.

♦ Solution ♦ :-

Given that

→ f(x) and g(x) be the two functions

→ f(x) = 3x²-2x+1

→ g(x) = 2x²-3x+7

Given that

→ f(x) = g(x)

⇒ 3x²-2x+1 = 2x²-3x+7

⇒ (3x²-2x+1) - (2x²-3x+7) = 0

⇒ 3x²-2x+1 -2x²+3x-7 = 0

⇒ (3x²-2x²)+(-2x+3x)+(1-7) = 0

⇒ x²+x-6 = 0

⇒ x²+3x-2x-6 = 0

⇒ x(x+3)-2(x+3) = 0

⇒ (x+3)(x-2) = 0

⇒ x+3 = 0 or x-2 = 0

∴ x = -3 or x = 2

♦ Answer ♦ :-

• The value of x are -3 and 2